i. Draw a rectangle of length 5cm and width
1 cm.
Draw a semicircle of diameter AE. Extend BC up to F. √5 is the side of the square BGHF.
ii. Draw a right-angled triangle of perpendicular sides 2 cm and 1cm.
Hypotenuse will be y is cm. The area of the square ACDE is 5 cm2 , because here we take the hypotenuse as sides of the square.
iii. Draw a right-angled triangle of hypotenuse 3 cm and one side 2cm.
Third side = (\sqrt{3^2-2^2}=\sqrt{5})cm
Draw a square having side BC, then area of the square BEDC will be 5cm2
