Variation of $log_(10)K$ with $(1)/(T)$ is shown by the following graph in which straight line is at $45^(@)$ , hence $Delta H^(@)$ is: A. $+4.606$ cal B. $-4.606$ cal C. 2 cal D. $-2$ cal
Correct Answer - B Slope of plot $= (-Delta H^(@))/(2.303 R) = 1$ $implies Delta H^(@) = - 2.303xx2 = - 4.606$ cal