Find the value of x for which the points (x, – 1), (2,1) and (4, 5) are collinear.
Solution: Let the points be A(x, -1), B(2, 1) and C(4, 5)
Now as the points are collinear, therefore
mAB = MBC
2 = 2(2 – x) = 4 – 2x
or 2x = 4 – 2
⇒ 2x = 2 ⇒ x = 1