For the following G.P.*, find Sn
3, 6, 12, 24, ...
3, 6, 12, 24,
Here, a = 3, r = $6/3$ = 2 > 1
Sn = $("a"("r"^"n" - 1))/("r" - 1)$, for r > 1
Sn = $(3(2^"n" - 1))/(2 - 1)$
Sn = 3(2n 1)