A steel girder of length l rests freely on two supports (Fig. 1.77). The moment of inertia of its cross-section is equal to I

Question 1

A steel girder of length l rests freely on two supports (Fig. 1.77). The moment of inertia of its cross-section is equal to I (see the foregoing problem). Neglecting the mass of the girder and assuming the sagging to he slight, find the deflection λ due to the force F applied to the middle of the girder.

Question 2

One can think of it as analogous to the previous case but with a beam of length l/2 loaded upward by a force F/2.

kratos · Answer 1 · 2020-02-19T22:20:31+0000

One can think of it as analogous to the previous case but with a beam of length l/2 loaded upward by a force F/2.

A steel girder of length l rests freely on two supports (Fig. 1.77). The moment of inertia of its cross-section is equal to I

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A steel girder of length l rests freely on two supports (Fig. 1.77). The moment of inertia of its cross-section is equal to I

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