A block of mass 0.5kg has an initial velocity of 10 m/* down an inclined plane 30°, the coefficient of friction between the block and the inclined surface is 0.2.
Doward acceleration
a = gsin30°-mu×gxcis30°
=10×1/2-0.2×10×√3/2
=5-√3 m/*^2
So velocity after moving 10 m downward
v^2=u^2+2×a×10
=>v^2= 10^2+2×(5-√3)×10
=v=13m/* (approx)