+3 votes
in Class 12 by kratos

Mr Smith has a bag A.Bag A has "n" numbers of bag B. Each bag B has " n " numbers of bag C. Each bag C has " n" number of one rupee coins in it.If one bag B is removed from bag A, then the total number of coins left in bag A is

(1) n(n-1)(n+1)

(2) n(n-1)

(3) n2 (n+1)

(4) n2(n-1)

1 Answer

+4 votes
by kratos
 
Best answer

Each bag C contains= n coins

thus, n no. of bag C contain = n × n= n²

Now n no. of bag C = 1 bag B

therefore 1 bag B contains =n² coins

If a bag B is removed from bag A, final no. of bag B in bag A = (n-1) [as there were n no. of bag B in bag A initially].

thus (n-1) no. of bag B will contain= (n-1) × n² coins

now bag A = (n-1) no. of bag B

Thus coins left in a bag

A is n²(n-1) [option 4]

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