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in Class 11 by kratos

Define : Addition Theorem of Probability.

1 Answer

+3 votes
by kratos
 
Best answer

(a) For Two Events. If A and B are two events associated with a random experiment, then

P(A ∪ B) = P(A) + P(B) – P(A ∩ B)

⇒ P(A or B) = P(A) + P(B) — P(A and B)

Corollary 1: If A and B are mutually exclusive events, then,

P(A ∩ B) = 0, therefore

P(A ∪ B) = P(A) + P(B)

Corollary 2: P(A or B) ≤ P((\underline{A})) + P(B)

Given, P(A ∪ B) = P(A) + P(B) – P(A ∩ B)

Since, P(A ∩ B) is greater than or equal to 0,

P(A or B) < P(A) + P(B)

Equality in the above result holds when A and B are mutually exclusive as P(A ∩ B) = 0

(b) For three events

If A, B and C be any three events associated with a random experiment, then

P(A ∪ B ∪ C) = P(A) + P(B) + P(C) – P(A ∩ B) – P(A ∩ C) – P(B ∩ C) + P(A ∩ B ∩ C)

Corollary 1: If A, B and C are mutually exclusive events, then

P(A ∩ B) = P(B ∩ C) = P(A ∩ C) = P(A ∩ B ∩ C) = 0

P(A ∪ B ∪ C) = P(A) + P(B) + P(C)

Note : (i) If A and B are two events such that A ⊆ B, then P(A) ≤ P(B)

(ii) If E is an event associated with a random experiment, then 0 P(E) ≤ 1

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