If a= 2i-3j+k,b=-i+k and c=2j-k. Find the area of parallelogram whose diagonals are a+b and b+c
D1 = a + b = i - 3j + 2k
D2 = b + c = -i + 2j
Area of parallelogram = 1/2 |D1x D2| => 1/2 |(i - 3j + 2k) x (-i + 2j)| => 1/2|-4i - 2j - k| => √21 / 2