In a rhombus, diagonals bisect each other at 90. Therefore, the given rhombus ABCD can be drawn as follows.
(1)A rough sketch of this rhombus ABCD is as follows.
(2) Draw a line segment AC of 5.2 cm and draw its perpendicular bisector. Let it intersect the line segment AC at point O.
(3) Draw arcs of 6.4 cm/2 = 3.2 cm on both sides of this perpendicular bisector. Let the arcs intersect the perpendicular bisector at point B and D.
(4) Join points B and D with points A and C.
ABCD is the required rhombus.
