125x+45x=2.27x
=>(5^x)^3+5^x(3^x)^2=2(3^x)^3
Taking 5^x=a and 3^x=b we get
a^3+ab^2-2b^3=0
=>a^3-b^3+ab^2-b^3=0
=>(a-b)(a^2+ab+b^2)+b^2(a-b)=0
=>(a-b)(a^2+ab+2b^2)=0
So a=b
=>5^x=3^x
=>(5/3)^x=1=(5/3)^0
Hence x=0
