+1 vote
in Class 9 by kratos

ABCD is a parallelogram whose diagonals intersect at O. If P is any point on BO, prove that:

(i) ar (∆ADO) = ar (∆CDO) (ii) ar (∆ABP) = ar (∆CBP)

1 Answer

+2 votes
by kratos
 
Best answer

Given that ABCD is a parallelogram

To prove: (i) ar (∆ADO) = ar (∆CDO)

(ii) ar (∆ABP) = ar (∆CBP)

Proof: We know that, diagonals of a parallelogram bisect each other

AO = OC and BO = OD

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