ABCD is a parallelogram whose diagonals intersect at O. If P is any point on BO, prove that:
(i) ar (∆ADO) = ar (∆CDO) (ii) ar (∆ABP) = ar (∆CBP)
Given that ABCD is a parallelogram
To prove: (i) ar (∆ADO) = ar (∆CDO)
(ii) ar (∆ABP) = ar (∆CBP)
Proof: We know that, diagonals of a parallelogram bisect each other
AO = OC and BO = OD