+1 vote
in Class 10 by kratos

In the given figure, if AB || DE, ∠BAC = 35 and ∠CDE = 53, find ∠DCE.

1 Answer

+3 votes
by kratos
 
Best answer

AB || DE and AE is a transversal

∠BAC = ∠CED (Alternate interior angles)

∠CED = 35

In ΔCDE,

∠CDE + ∠CED + ∠DCE = 180 (Angle sum property of a triangle)

53 + 35 + ∠DCE = 180

∠DCE = 180 − 88

∠DCE = 92

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