In the given figure, if AB || DE, ∠BAC = 35 and ∠CDE = 53, find ∠DCE.
AB || DE and AE is a transversal
∠BAC = ∠CED (Alternate interior angles)
∠CED = 35
In ΔCDE,
∠CDE + ∠CED + ∠DCE = 180 (Angle sum property of a triangle)
53 + 35 + ∠DCE = 180
∠DCE = 180 − 88
∠DCE = 92