If A = cos2θ + sin4θ for all values of θ, then prove that 3/4≤A≤1
We have A =cos2θ + sin4θ = cos2θ + sin2θ sin2θ ≤ cos2θ + sin2θ
Therefore, A ≤ 1
Also, A = cos2θ + sin4θ = (1 – sin2θ) + sin4θ
Hence, 3/4≤A≤1