+3 votes
in JEE by kratos

Find the value of tan 9° – tan 27° – tan 63° + tan 81°

1 Answer

+4 votes
by kratos
 
Best answer

We have

tan9° – tan 27° – tan 63° + tan 81°

= tan 9° + tan 81° – tan 27° – tan 63°

= tan 9° + tan (90° – 9°) – tan 27° – tan (90° – 27°)

= tan 9° + cot 9° – (tan 27° + cot 27°) ....(1)

Also

tan 9° + cot 9° = 1/(sin 9° cos9°) = 2/sin18° ......(2)

Similarly, tan 27° + cot 27°

= 2/cos36° .....(3)

Using (2) and (3) in (1), we get

tan 9° – tan 27° – tan 63° + tan 81°

...