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Prove that (sec8θ - 1)/(sec4θ - 1) = tan8θ/ tan2θ
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Mar 22, 2018
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JEE
by
kratos
Prove that (sec8θ - 1)/(sec4θ - 1) = tan8θ/ tan2θ
trigonometry function
jee
jee mains
class-11
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answered
Sep 18, 2020
by
kratos
Best answer
We have
(sec8θ - 1)/(sec4θ - 1)
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