+3 votes
in Class 9 by kratos

Relation between electrochemical equivalent (e) and equivalent mass (E) is given by
A. $E = (e)/(96500)$
B. $E = (96500)/(e)$
C. $e = (E)/(96500)$
D. $e = ("valency")/(96500)$

1 Answer

+2 votes
by kratos
 
Best answer

The relation between electrochemical equivalent (c) and equivalent mass (E) is given by $e = (E)/(96500).$

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