=> The molar mass of Calcium Carbonate is 100 g/mole,
We have 200 g, therefore, we have 2 *****,
the number of molecule per mole is 6.02 x 1023,
Therefore we have 1.204 x 1024 molecules.
=> Molecular mass of CaCO3 = 40 + 12 + (3 x 16) = 100 g [Molecular weight of Ca = 40, C = 12, O =16]
1 mole of Oxygen atoms = 6.022 x 1023 Oxygen atoms (Avogadro’* number)
1 mole of Calcium Carbonate = 100 g of Calcium Carbonate
100 g of Calcium Carbonate has 3 ***** of Oxygen atoms = 3 x 6.022 x 1023 Oxygen atoms.
So, 200 g of Calcium Carbonate has 6 *** of Oxygen atoms = 6 x 6.022 x 1023 Oxygen atoms.**u200b
