Using ruler and compasses only, construct a ∆ABC, given base BC = 7cm, ∠ABC = 60° and AB + AC = 12 cm.
Steps of construction:
Draw a line segment BC of 7 cm
At B, draw an angle XBC of 60o
With center B and radius 12 cm draw an arc which intersects BX at D.
Join DC
Draw the perpendicular bisector of DC which intersects BD at A.
Join AC
∆ABC is the required triangle.