+1 vote
in JEE by kratos

The total number of 9 digit numbers which have all different digits is

(A) 10!

(B) 9 !

(C) 9 × 9!

(D) 10×10!

1 Answer

+4 votes
by kratos
 
Best answer

Answer is (C)

We have to form 9-digit number which has all different digit.

First digit from the left can be filled in 9 ways (excluding ‘0’).

Now nine digits are left including ‘O’.

So remaining eight places can be filled with these nine digits in 9P8 ways

So, total number of numbers = 9 x 9P8 = 9×9!

...