If in two triangles ABC and PQR, AB/QR = BC/PR = CA/PQ, then
(A)Δ PQR ~ Δ CAB (B) Δ PQR ~Δ ABC
(C)Δ CBA ~ Δ PQR (D) Δ BCA ~ Δ PQR
Correct answer is (A)Δ PQR ~ Δ CAB
