In the figure, if AB || DE, ∠ BAC = 35° and ∠CDE = 53°, find ∠ DCE.
In the given figure
∠BAC = ∠CED [Alternate angles]
⇒ ∠CED = 35°
In ∆CDE,
∠CDE + ∠DCE + ∠CED = 180° [Angle sum property of a triangle]
⇒ 53° + ∠DCE + 35° = 180°
⇒ ∠DCE + 88° = 180°
⇒ ∠DCE = 180° – 88° = 92°
Hence, ∠DCE = 92° Ans