Find the area of the minor segment of a circle of radius 14 cm, when the angle of the corresponding sector is 60°.
Solution:
Given that, radius of circle (r) = 14 cm
and angle of the corresponding sector i.e., central angle (θ) = 60°
Since, in ΔAOB, OA = OB = Radius of circle i.e., ΔAOB is isosceles.