Correct Answer - D
We find that $P(E(1))=(6)/(36),P(E(2))=(6)/(36)=(1)/(6)$,
$P(E(3))=(1)/(2),P(E(1) cap E(2))=(1)/(36), P(E(2) cap E(3))=(3)/(36)=(1)/(12)$,
$P(E(1) cap E(3))=(3)/(36)=(1)/(12) " and " P(E(1) cap E(2) cap E(3))=0$
Clearly, $P(E(1) cap E(2))=P(E(1))P(E(2)) implies E(1), E(2)$ are independent
$P(E(1) cap E(3))=P(E(1))P(E(3)) implies E(1), E(3)$ are independent
But, $P(E(1) cap E(2) cap E(3)) ne P(E(1))P(E(2))P(E(3))$
$implies E(1),E(2),E_(3)$ are not independent
Thus, option (d) is incorrect.