The HCF of two numbers is 27 and their LCM is 162. If one of the numbers is 54, what is the other number?
(a) 36 (b) 45 (c) 9 (d) 81
(d) 81
Let the two numbers be x and y.
It is given that: x = 54
HCF = 27
LCM = 162
We know,
x × y = HCF × LCM
⇒ 54 × y = 27 × 162
⇒ 54 y = 4374
⇒ ∴ y = 4374/54
= 81