The given equations are:
(7 − 4x)/ 3 = y
⇒ 4x + 3y = 7 ……..(i)
and 2x + 3y + 1 = 0
⇒2x + 3y = -1 ……….(ii)
On subtracting (ii) from (i), we get:
2x = 8
⇒x = 4
On substituting x = 4 in (i), we get:
16x + 3y = 7
⇒3y = (7 – 16) = -9
⇒y = -3
Hence, the solution is x = 4 and y = -3.
