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in JEE by kratos

A simple harmonic oscillator is represented by the equation : Y = 0.40 Sin (440t+0.61)

Y is in metres

t is in seconds

Find the values of 1) Amplitude 2) Angular frequency 3) Frequency of oscillation 4) Time ** of oscillation, 5) Initial phase.

1 Answer

+1 vote
by kratos
 
Best answer

The given equation is:- Y = 0.40 Sin (440t + 0.61)

Comparing it with equation of *.H.M. Y = a Sin (w t +∅0 )

1) Amplitude = a = 0.40m

2) Angular frequency = w = 440Hz

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