Let fixed charges be Rs.x and rate per km be Rs.y.
Then as per the question
x + 80y = 1330 ………(i)
x + 90y = 1490 ……..(ii)
Subtracting (i) from (ii), we get
10y = 160
⇒ y = 160/10 = 16
Now, putting y = 16, we have
x + 80 × 16 = 1330
⇒x = 1330 – 1280 = 50
Hence, the fixed charges be Rs.50 and the rate per km is Rs.16.