$49 g$ of $H(2) SO(4)$ is disslved in enough water to make one litre of a soltuion of density $1.049 g c c^(-1)$. Find the molarity, normality, moality, and mole fraction of $H(2) SO(4)$ in the solution.
Correct Answer - A i. $M = (W(2) xx 100)/(Mw(2) xx V(sol) ("in" mL)) = (49 xx 1000)/(98 xx 1000) = 0.5 M$ ii. $m = (W(2) xx 1000)/(Mw(2) xx W(1)) ({:(W(1)=V("Sol")xxd("sol")-W(2)),(=1000xx1.049-49),(=1000g):})$ $= (49 xx 1000)/(98 xx 1000) = 0.5 m$ iv. $X(2) = (W(2) // Mw(2))/((W(1))/(Mw(1)) + (W(2))/(Mw_(2))) = (49 // 98)/((100)/(18) + (49)/(98)) = (0.5)/(55.5 + 0.5)$ $(0.5)/(56) = 0.009$
