Question

If tan θ = a/b, show that (a sinθ - b cosθ)/ a sinθ + b cosθ) = (a2 - b2)/a2 + b2

Answer 1

It is given that tan θ = a/b

LHS = (a sinθ - b cosθ)/ a sinθ + b cosθ)

Dividing the numerator and denominator by cos θ, we get: