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in Class 11 by kratos

Find the coefficient of x5 in (x + 3)8

1 Answer

+3 votes
by kratos
 
Best answer

It is known that (r + 1)th term, (Tr+1), in the binomial expansion of (a + b)n is given by

Assuming that x5 occurs in the (r + 1)th term of the expansion (x + 3)8, we obtain

Comparing the indices of x in x5and in Tr +1,

we obtain r = 3

Thus, the coefficient of x5 is

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