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Find the roots of x^2u200bu200bu200bu200bu200bu200bu200b = 18x -77
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asked
Apr 5, 2018
in
JEE
by
kratos
Find the roots of x2 = 18x -77
jee
function
quadratic equations
class-10
domain and range of a function
jee mains
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+6
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answered
Jan 16, 2020
by
kratos
Best answer
Hence, 7 and 11 are the roots of the equation x2 = 18x -77
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