A compound forms hexagonal close-packed structure

Question 1

A compound forms hexagonal close-packed structure. What is the total number of voids in 0.5 mol of it? How many of these are tetrahedral voids?

Question 2

Number of close-packed particles = 0.5 × 6.022 × 1023 = 3.011 × 1023

Therefore, number of octahedral voids = 3.011 × 1023 And,

number of tetrahedral voids = 2 × 3.011 × 1023 = 6.022 ×1023

Therefore, total number of voids = 3.011 × 1023 + 6.022 × 1023 = 9.033 × 1023

kratos · Answer 1 · 2021-03-15T21:29:53+0000

Number of close-packed particles = 0.5 × 6.022 × 1023 = 3.011 × 1023

Therefore, number of octahedral voids = 3.011 × 1023 And,

number of tetrahedral voids = 2 × 3.011 × 1023 = 6.022 ×1023

Therefore, total number of voids = 3.011 × 1023 + 6.022 × 1023 = 9.033 × 1023

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