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In triangle ABC, AD is perpendicular to side BC and AD^2 = BD × DC. Show that angle BAC = 90°

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asked Mar 5, 2019 in Class 10 by kratos

In triangle ABC, AD is perpendicular to side BC and AD2 = BD × DC. Show that angle BAC = 90°

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class-10
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1 Answer

+3 votes

answered Feb 7, 2021 by kratos

Best answer

Given AD2 = BD × DC

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