In the given figure, ABC is a triangle. DE is parallel to BC and AD/DB = 3/2
(i) Determine the ratios AD/AB and DE/BC
(ii) Prove that ΔDEF is similar to ΔCBF Hence, find EF/FB.
(iii) What is the ratio of the areas of ΔDEF and ΔBFC.
(iii) Since the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides, therefore.
