In the given figure, ΔABC is right-angled at B such that BC = 6 cm and AB = 8 cm. A circle with centre O has been inscribed the triangle. OP ⊥ AB, OQ ⊥ BC and OR ⊥ AC. If OP = OQ = OR = x cm then x = ?
(a) 2 cm (b) 2.5 cm (c) 3 cm (d) 3.5 cm
(a) 2 cm
PBQO is a square
CR = CQ ( Since the lengths of tangents drawn from an external point are equal)
