Question

In the given figure ABCD is a quadrilateral in which ∠ABC = 90°, ∠BDC = 90°, AC = 17 cm, BC = 15 cm, BD = 12 cm and CD = 9 cm. The area of quadrilateral ABCD is

Answer 1

(b) 114 cm2

Using Pythagoras theorem in ΔABC, we get:

= 1/2 x 12 x 9

= 54 cm2