Question

lf two zeroes of the polynomial p(x) = x4 - 6x3 - 26x2 + 138x - 35 are 2 ± √3. find the other zeroes.

Answer 1

As 2 ± √3 are the zeroes of p(x), so x - (2 ± √3) are the factors of p(x).

and the product of factors,

Hence, other two zeroes of p(x) are -5 and 7.