Construct a triangle ABC with BC = 7 cm, ∠B = 60°and AB = 6 cm. Construct another triangle whose sides are 3/4 of the corresponding sides of ΔABC.
Steps of construction :
At point B draw a line BA making an angle of 60°.
With centre C mark an arc A of length 6 cm.
Join CA.
Draw a ray BX making an acute angle with BC.
Locate four points B1, B2, B2 and B4, on the line segment BX at equal distance.
Join B4C. Draw a parallel line through B, to B4C intersecting line segment BC at C'.
Through C' draw a line parallel to AC intersecting extended line segment AB at A'.
Hence ΔA'BC' is the required triangle.