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In a right triangle ABC, right angled at C. P and Q are points of the sides CA and. CB respectively, which divide these sides in the ratio 2 : 1.

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in Mathematics by kratos

In a right triangle ABC, right angled at C. P and Q are points of the sides CA and. CB respectively, which divide these sides in the ratio 2 : 1.

Prove that : 9AQ2 = 9AC2 + 4BC2

9BP2 = 9BC2 + 4AC2

9(AQ2 +BP2) = 13 AB2

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by kratos
 
Best answer

Since P divides AC in the ratio 2 :1

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