For the reaction; N2(g) + 3H2(g ⇌ 2NH3(g).
At 400 K, Kp = 41 atm-2 .Find the value of Kp for each of the following reactions at the same temperature:
(i) 2NH3(g) ⇌ N2(g) + 3H2(g)
(ii) 1/2N2(g) + 3/2H2(g)⇌ NH3(g)
(iii) 2N2(g) +6H2(g)⇌ 4NH3(g)
= (41)2 = 1.681 x103 atm -4