+2 votes
in JEE by kratos

The differential equation of all circles passing through the origin and having their centres on the X-axis is

(a) x2 = y2 + xydy/dx

(b) x2 = y2 + 3xydy/dx

(c) y2 = x2 + 2xydy/dx

(d) y2 = x2 - 2xydy/dx

1 Answer

+5 votes
by kratos
 
Best answer

Correct option (c) y2 = x2 + 2xydy/dx

Explanation:

General equation of all such circles which pass through the origin and whose centre lie on X-axis, is

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