+2 votes
in Class 12 by kratos

A compound of vanadium has a magnetic moment of 1.73 BM. The electronic configuration of the vanadium ion in this compound is (V =23).

(a) 1s2, 2s2, 2p6, 3s2, 3p6, 3d3, 4s2

(b) 1s2, 2s2, 2p6, 3s2, 3p6, 3d1

(c) 1s2, 2s2, 2p6, 3s2, 3p6, 3d3

(d) 1s2, 2s2, 2p6, 3s2, 3p6, 3d2

1 Answer

+5 votes
by kratos
 
Best answer

Correct option (b) 1s2, 2s2, 2p6, 3s2, 3p6, 3d1

Explanation:

On solving, we get n = 1

Thus, V contains only one unpaired electron and its electronic configuration is

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