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Acetyl bromide reacts with excess of CH3MgI followed by treatment with a

+3 votes
in JEE by kratos

Acetyl bromide reacts with excess of CH3MgI followed by treatment with a saturated solution of NH4Cl gives

(a) acetone

(b) acetamide

(c) 2-methyl-2-propanol

(d) acetyl iodide

1 Answer

+6 votes
by kratos
 
Best answer

Correct Option(c) 2-methyl-2-propanol

Explanation:

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