+3 votes
in JEE by kratos

The solubility product of Ca(OH)2 at 25°C is 4.42 x 10-5. A 500 mL of saturated solution of Ca(OH)2 is mixed with equal volume of 0.4 M NaOH. Now the amount of Ca(OH)2 precipitated is (in mg)

(a) O.0223

(b) 0.01115

(c) 0.010045

(d) 0.001105

1 Answer

+6 votes
by kratos
 
Best answer

Correct Option (c) 0.010045

Explanation:

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