+3 votes
in Class 12 by kratos

An element crystallises in fcc lattice with cell edge of 400 pm. Calculate its density it 250 g of this element contain 2.5 x 1024 atoms.

1 Answer

+1 vote
by kratos
 
Best answer

In fcc, z = 4;

d = (z x M)/a3 x NA (i)

No. of atoms = (w/M) x NA

2.5 x 1024 = (250g/M) x NA

M = [250 x NA]/2.5 x 1024 (ii)

Putting values of M in equation (i)

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