Calculate the emf of the following cell at 298 K Cr(*)/Cr^3+ + (0.1 M)//Fe^2+ (0.01 M)/Fe(*)

Question

(i) Calculate the emf of the following cell at 298 K Cr()/Cr3+ + (0.1 M)//Fe2+ (0.01 M)/Fe()

[Given: E°cell = + 0.30 V]

(ii) The conductivity of 10-3 mol/L acetic acid at 25°C is 4.1 x 10-5 cm-1. Calculate its degree of dissociation, if ^m0 for acetic acid at 25°C is 390.5 cm2 mol-1.

Answer 1

(i) 2Cr() + 3Fe2+(aq) → 3Fe() + 2Cr3+(aq.)

n = 6

(ii)