The correct option is (b) 5.6 x 104 N.
Explanation:
The shearing stress is exerted on the rectangular surface (2 cm x 0.2 cm) that is the boundary of the ****. The area of this surface
A = 2 x 10-2 x 4 x 0.2 x 10-2 m2
= 1.6 x 10-4 m2
Minimum shearing stress to rupture the steel sheet
= (F/A)min = 3.5 x 108 N/m2
Force = 3.5 x 108 x 1.6 x 10-4
= 5.6 x 104 N