+1 vote
in General by kratos

Factorise63a2 112b2

1 Answer

+2 votes
by kratos
 
Best answer

63a2 112b2= 7(9a2 16b2)

= 7[(3*a*)2 (4*b*)2]

= 7(3a+ 4b) (3a 4b) [*a*2*b*2= (*a**b*) (*a*+*b*)]

...