Question

Factorise :64 - a3b3

Answer 1

64 - a3b3
= (4)3 - (ab)3
= ( 4 - ab )[(4)2 + 4 x ab + (ab)2 ] [ a3 - b3 = ( a - b )( a2 + ab + b2 )]
= ( 4 - ab )( 16 + 4ab + a2b2 )